![Is it necessary to connect the CC1/CC2 pins to ground with a 5.1k resistor? I would like to make a pcb which has a female usb type c port which converts to Is it necessary to connect the CC1/CC2 pins to ground with a 5.1k resistor? I would like to make a pcb which has a female usb type c port which converts to](https://preview.redd.it/is-it-necessary-to-connect-the-cc1-cc2-pins-to-ground-with-v0-7jptrmvwlr0a1.png?width=363&format=png&auto=webp&s=18d71f5b649eb909902fb89fbe8aab826541ddd9)
Is it necessary to connect the CC1/CC2 pins to ground with a 5.1k resistor? I would like to make a pcb which has a female usb type c port which converts to
![Share about Firmware-Hardware and the latest USB Type-C PD technology. : USB Type-C Configuration Channel (CC) pin function (English version) Share about Firmware-Hardware and the latest USB Type-C PD technology. : USB Type-C Configuration Channel (CC) pin function (English version)](http://1.bp.blogspot.com/-MeDQDtxyuSE/U_F-lcfK78I/AAAAAAAAAfM/2kMzMfo8GIE/s1600/TypeC_host_device.jpg)
Share about Firmware-Hardware and the latest USB Type-C PD technology. : USB Type-C Configuration Channel (CC) pin function (English version)
![usb c - Can USB Type-C 2.0 upstream (device) connect its CC pins and share a pull-down? - Electrical Engineering Stack Exchange usb c - Can USB Type-C 2.0 upstream (device) connect its CC pins and share a pull-down? - Electrical Engineering Stack Exchange](https://i.stack.imgur.com/Hb6M5.png)
usb c - Can USB Type-C 2.0 upstream (device) connect its CC pins and share a pull-down? - Electrical Engineering Stack Exchange
![Is it necessary to connect the CC1/CC2 pins to ground with a 5.1k resistor? I would like to make a pcb which has a female usb type c port which converts to Is it necessary to connect the CC1/CC2 pins to ground with a 5.1k resistor? I would like to make a pcb which has a female usb type c port which converts to](https://i.redd.it/is-it-necessary-to-connect-the-cc1-cc2-pins-to-ground-with-v0-1jgv4d4glr0a1.png?width=663&format=png&auto=webp&s=00df2e03cc0f3265b6b6dcb81682420534b006f7)