![So Y equals R cubed over three. And if you determine the rate of change in this curve correctly, I think you will be pleasanelty surprised... Well, don't you get it Bart? So Y equals R cubed over three. And if you determine the rate of change in this curve correctly, I think you will be pleasanelty surprised... Well, don't you get it Bart?](https://external-preview.redd.it/7EXbmtiqKJm9vW-oXNDRUdM2p9efEPP8QVYep10VtXg.jpg?auto=webp&s=340cdc1a658097201327a258cb96aa518f97be2d)
So Y equals R cubed over three. And if you determine the rate of change in this curve correctly, I think you will be pleasanelty surprised... Well, don't you get it Bart?
![Point R and T are each a distance d from each of the two particles with equal positive charges as shown. If k = \frac{1}{4 \pi \epsilon_0}, the work required to move Point R and T are each a distance d from each of the two particles with equal positive charges as shown. If k = \frac{1}{4 \pi \epsilon_0}, the work required to move](https://homework.study.com/cimages/multimages/16/es24977278675383053478993.png)
Point R and T are each a distance d from each of the two particles with equal positive charges as shown. If k = \frac{1}{4 \pi \epsilon_0}, the work required to move
![If Tr = ^2016Crx^2016 - r , for r = 0, 1, ,....2016 , then (T0 - T2 + T4.... + T2016)^2 + (T1 - T3 + T5....T2015)^2 is equal to - If Tr = ^2016Crx^2016 - r , for r = 0, 1, ,....2016 , then (T0 - T2 + T4.... + T2016)^2 + (T1 - T3 + T5....T2015)^2 is equal to -](https://dwes9vv9u0550.cloudfront.net/images/3952961/792dfa8e-ee2a-4599-8b84-b82c9bb1d049.jpg)
If Tr = ^2016Crx^2016 - r , for r = 0, 1, ,....2016 , then (T0 - T2 + T4.... + T2016)^2 + (T1 - T3 + T5....T2015)^2 is equal to -
![A particle moving in a circle of radius R with a uniform speed takes a time T to complete one revolu - YouTube A particle moving in a circle of radius R with a uniform speed takes a time T to complete one revolu - YouTube](https://i.ytimg.com/vi/9kAs_nj3nX8/maxresdefault.jpg)
A particle moving in a circle of radius R with a uniform speed takes a time T to complete one revolu - YouTube
![Given that P=Q=R. If vec(P)+vec(Q)=vec(R) then the angle between vec(P) and vec(R) is theta(1). If vec(P)+vec(Q)+vec(R)=vec(0) then the angle between vec(P) and vec(R) is theta(2). The relation between theta(1) and theta(2) is :- Given that P=Q=R. If vec(P)+vec(Q)=vec(R) then the angle between vec(P) and vec(R) is theta(1). If vec(P)+vec(Q)+vec(R)=vec(0) then the angle between vec(P) and vec(R) is theta(2). The relation between theta(1) and theta(2) is :-](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/642715325_web.png)